Suggested: find the fourier series of f(x)=2x-x^2 in (0 3) - sin^2(2x+5) integration - sin 2(2x+1) differentiation - derivative of sin^2(2x) - integral of sin^2(2x) - cos^4x+sin^4x=1/2(2-sin^2 2x) - tan1/2 sin^(- 1)(2x)/(1+x^2)+cos^(- 1)(1-y^2)/(1+y^2) - cos(pi+x)cos(-x)/sin(pi-x)cos(pi/2+x)=cot^2x - sin^8x-cos^8x=(sin^2x-cos^2x)(1-2 sin^2x cos^2x) - d^3-7dd'^2-6d'^3=sin(x+2y)+e^2x+y - sin inverse 2x/1+x^2 integration - y=sin inverse (2x/1+x^2) - integration of sin^-1(2x/1+x^2) - solve (d2+1)y=x^2 sin 2x - sin^2(2x) Browse related:
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